BlackBox Component Builder Forums

Posted: **Mon Jan 19, 2015 12:15 pm**

I find somehow disturbing that ENTIER(Math.Power(5, 3)) = 124
because j = 125 if
x := Math.Power(5, 3);
j := ENTIER(x);

Code: Select all

PROCEDURE PowerEntier*;
	VAR x, y: REAL; xe, ye, k: LONGINT;
BEGIN
	x := Math.Power(5, 3); y := 5.0 * 5.0 * 5.0;
	xe := ENTIER(x); ye := ENTIER(y);
	k := ENTIER(Math.Power(5, 3)); (* !! *)
	StdLog.String("x = "); StdLog.Real(x); StdLog.Ln;
	StdLog.String("y = "); StdLog.Real(y); StdLog.Ln;
	StdLog.String("xe = "); StdLog.Int(xe); StdLog.Ln;
	StdLog.String("ye = "); StdLog.Int(ye); StdLog.Ln;
	StdLog.String("k = "); StdLog.Int(k); StdLog.Ln; (* !! *)
	StdLog.Bool(Math.Power(5, 3) = 5.0 * 5.0 * 5.0); StdLog.Ln; (* !! *)
	StdLog.Real(Math.Power(5, 3) - 5.0 * 5.0 * 5.0); StdLog.Ln; (* !! *)
	StdLog.Ln
END PowerEntier;

x =  125.0
y =  125.0
xe =  125
ye =  125
k =  124
 $FALSE
 -1.387778780781446E-17

Posted: **Mon Jan 19, 2015 12:32 pm**

1. Read the discussion Numerical Analysis (including the references regarding rounding) contained in some of those posts.

2. For this particular example use Math.IntPower to get the answer you want.

Posted: **Mon Jan 19, 2015 12:41 pm**

Thanks,
I did not notice about Math.IntPower

BlackBox Component Builder Forums

ENTIER(Math.Power(5, 3)) = 124

ENTIER(Math.Power(5, 3)) = 124

Re: ENTIER(Math.Power(5, 3)) = 124

Re: ENTIER(Math.Power(5, 3)) = 124